18x^2=-10x

Solution for 18x^2=-10x equation:

18x^2=-10x

We move all terms to the left:

18x^2-(-10x)=0

We get rid of parentheses

18x^2+10x=0

a = 18; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·18·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*18}=\frac{-20}{36}
=-5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*18}=\frac{0}{36}
=0
$